Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 534: 17

Answer

$x=\{ -2,0,2 \}$

Work Step by Step

Using factoring, the given equation, $ x^3=4x $, is equivalent to \begin{array}{l}\require{cancel} x^3-4x=0 \\\\ x(x^2-4)=0 \\\\ x(x+2)(x-2)=0 .\end{array} Equating each factor to $0$, then, \begin{array}{l}\require{cancel} x=0 ,\\\\\text{OR}\\\\ x+2=0 \\\\ x=-2 ,\\\\\text{OR}\\\\ x-2=0 \\\\ x=2 .\end{array} Hence, $ x=\{ -2,0,2 \} .$
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