Answer
$2/9= x$
Work Step by Step
$\sqrt {2x+5} + \sqrt {2x} =3$
$\sqrt {2x+5} + \sqrt {2x} - \sqrt {2x} =3- \sqrt {2x}$
$\sqrt {2x+5} = 3 - \sqrt {2x}$
$(\sqrt {2x+5})^2 = (3 - \sqrt {2x})^2$
$(2x+5) =(3-\sqrt {2x})*(3-\sqrt {2x})$
$2x+5 = 3*3+3*-\sqrt {2x}+3*-\sqrt {2x}+(-\sqrt {2x}*-\sqrt {2x})$
$2x+5 = 9-6\sqrt {2x} + 2x$
$2x+5-9-2x = 9-6\sqrt {2x} + 2x -9-2x$
$-4 = -6\sqrt {2x}$
$-4/-6 =-6\sqrt {2x}/-6$
$2/3 =\sqrt {2x}$
$(2/3)^2 =(\sqrt {2x})^2$
$4/9 = 2x$
$4/9*1/2 = 2x*1/2$
$4/18 = x$
$2/9= x$
