Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 534: 39c

Answer

$3z^{2}\sqrt[4] {z^{3}}$

Work Step by Step

$\sqrt[4] {81z^{11}}$ =$\sqrt[4] {3^{4}\times z^{8}\times z^{3}}$ =$\sqrt[4] {3^{4}}\times \sqrt[4] {z^{8}}\times \sqrt[4] {z^{3}}$ =$3\times z^{2}\times \sqrt[4] {z^{3}}$ =$3z^{2}\sqrt[4] {z^{3}}$
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