Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 534: 20

Answer

$-(x-2)$

Work Step by Step

$\frac{x^{2}-4x+4}{2-x}$ =$\frac{x^{2}-2x-2x+4}{2-x}$ =$\frac{x(x-2)-2(x-2)}{-(x-2)}$ =$\frac{(x-2)(x-2)}{-(x-2)}$ =$\frac{(x-2)}{-1}$ =$-(x-2)$
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