Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 534: 40b

Answer

$2a^{2}b^{3}\sqrt[3] {3a}$

Work Step by Step

$\sqrt[3] {24a^{7}b^{9}}$ =$\sqrt[3] {8\times3\times a^{6}\times a \times b^{9}}$ =$\sqrt[3] {8\times a^{6} \times b^{9}\times3\times a}$ =$\sqrt[3] {2^{3}\times a^{6}\times b^{9}}\times \sqrt[3] {3\times a}$ =$2a^{2}b^{3}\times \sqrt[3] {3\times a}$ =$2a^{2}b^{3}\sqrt[3] {3a}$
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