Answer
$\frac{1}{2}$
Work Step by Step
$2(a^{2}+2)-8=-2a(a-2)-5$
$2a^{2}+4-8=-2a^{2}+4a-5$
$2a^{2}+2a^{2}-4a+4-8+5=0$
$4a^{2}-4a+1=0$
$4a^{2}-2a-2a+1=0$
$2a(2a-1)-1(2a-1)=0$
$(2a-1)(2a-1)=0$
$a=\frac{1}{2}$ and $a=\frac{1}{2}$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 8 - Cumulative Review - Page 534: 16
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