Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 534: 42b

Answer

$x^{2}-2x\sqrt 5+5$

Work Step by Step

$(\sqrt 5-x)^{2}$ =$(\sqrt 5-x)(\sqrt 5-x)$ =$\sqrt 5(\sqrt 5-x)-x(\sqrt 5-x)$ =$\sqrt 5\sqrt 5-x\sqrt 5-x\sqrt 5+x^{2}$ =$5-2x\sqrt 5+x^{2}$ =$x^{2}-2x\sqrt 5+5$
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