Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 534: 25

Answer

$3x^{3}y-15x-1-\frac{6}{xy}$

Work Step by Step

$\frac{3x^{5}y^{2}-15x^{3}y-x^{2}y-6x}{x^{2}y}$ =$\frac{3x^{5}y^{2}}{x^{2}y}-\frac{15x^{3}y}{x^{2}y}-\frac{x^{2}y}{x^{2}y}-\frac{6x}{x^{2}y}$ =$3x^{5-2}y^{2-1}-15x^{3-2}-1-\frac{6}{x^{2-1}y}$ =$3x^{3}y^{1}-15x^{1}-1-\frac{6}{x^{1}y}$ =$3x^{3}y-15x-1-\frac{6}{xy}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.