Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 534: 40c

Answer

$2x^{2}\sqrt[4] {3x}$

Work Step by Step

$\sqrt[4] {48x^{9}}$ =$\sqrt[4] {16\times3\times x^{8}\times x}$ =$\sqrt[4] {2^{4}\times3\times x^{8}\times x}$ =$\sqrt[4] {2^{4}\times x^{8}\times 3\times x}$ =$\sqrt[4] {2^{4}\times x^{8}}\times \sqrt[4] {3\times x}$ =$2\times x^{2}\times \sqrt[4] {3\times x}$ =$2x^{2}\sqrt[4] {3x}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.