Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 93

Answer

$17\sqrt{2}-15\sqrt{5}$

Work Step by Step

Using the properties of radicals, the expression $ 2\sqrt{50}-3\sqrt{125}+\sqrt{98} $ simplifies to \begin{array}{l} 2\sqrt{25\cdot2}-3\sqrt{25\cdot5}+\sqrt{49\cdot2} \\= 2\cdot5\sqrt{2}-3\cdot5\sqrt{5}+7\sqrt{2} \\= 10\sqrt{2}-15\sqrt{5}+7\sqrt{2} \\= (10\sqrt{2}+7\sqrt{2})-15\sqrt{5} \\= 17\sqrt{2}-15\sqrt{5} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.