Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 63

Answer

$2\sqrt 15$

Work Step by Step

$\sqrt 60=\sqrt (4\times15)=\sqrt 4\times\sqrt 15=2\sqrt 15$ We know that $\sqrt 4=2$, because $2^{2}=4$.
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