Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 469: 76

Answer

$\sqrt 130\approx11.402$ units

Work Step by Step

We know that the distance $d$ between two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given by $d=\sqrt ((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2})$. Therefore, the distance between the points (-4,-6) and (-1,5) is $d=\sqrt ((-1-(-4))^{2}+(5-(-6))^{2})=\sqrt ((3)^{2}+(11)^{2})=\sqrt (9+121)=\sqrt 130\approx11.402$ units
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