## Intermediate Algebra (6th Edition)

$\frac{5}{\sqrt \pi}$ meters
We are given that the radius of a circle of area A is given by the function $r=\sqrt (\frac{A}{\pi})$. Furthermore, we are given that the area of the circle is 25 square meters. Therefore, $r=\sqrt (\frac{25}{\pi})=\frac{\sqrt 25}{\sqrt \pi}=\frac{5}{\sqrt \pi}$ meters. We know that $\sqrt 25=5$, because $5^{2}=25$.