Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 91

Answer

$\dfrac{15+2\sqrt{3}}{6}$

Work Step by Step

Using the properties of radicals, the expression $ \dfrac{5}{\sqrt[]{4}}+\dfrac{\sqrt[]{3}}{3} $ simplifies to \begin{array}{l} \dfrac{5}{2}+\dfrac{\sqrt[]{3}}{3} \\\\= \dfrac{3(5)+2\sqrt{3}}{6} \\\\= \dfrac{15+2\sqrt{3}}{6} .\end{array}
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