## Intermediate Algebra (6th Edition)

$105^{-\frac{2}{3}}=\frac{1}{105^{\frac{2}{3}}}=\frac{1}{\sqrt[3] (105^{2})}=.045$ In this case, we are finding the reciprocal of $\sqrt[3] (105^{2})=22.257$. $\frac{1}{22.257}=.045$