## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 7 - Review: 100

#### Answer

$\sqrt[3]{a^2}+4\sqrt[3]{a}+4$

#### Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ , the expression $(\sqrt[3]{a}+2)^2$ simplifies to \begin{array}{l} (\sqrt[3]{a})^2+2(\sqrt[3]{a})(2)+(2)^2 \\= \sqrt[3]{a^2}+4\sqrt[3]{a}+4 .\end{array}

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