Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 469: 99

Answer

$a-9$

Work Step by Step

Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the expression $ (\sqrt{a}+3)(\sqrt{a}-3) $ simplifies to \begin{array}{l} (\sqrt{a})^2-(3)^2 \\= a-9 .\end{array}
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