Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 86

Answer

$\left( \sqrt{3},-3\sqrt{6} \right)$

Work Step by Step

Using $\left( \dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2} \right)$ or the Midpoint Formula, then the midpoint of the line segment joing the given points, $ \left( \sqrt{3},-2\sqrt{6} \right) \text{ and } \left( \sqrt{3},-4\sqrt{6} \right) ,$ is \begin{array}{l}\require{cancel} \left( \dfrac{\sqrt{3}+\sqrt{3}}{2},\dfrac{-2\sqrt{6}+(-4\sqrt{6})}{2} \right) \\\\= \left( \dfrac{\sqrt{3}+\sqrt{3}}{2},\dfrac{-2\sqrt{6}-4\sqrt{6}}{2} \right) \\\\= \left( \dfrac{2\sqrt{3}}{2},\dfrac{-6\sqrt{6}}{2} \right) \\\\= \left( \sqrt{3},-3\sqrt{6} \right) .\end{array}
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