Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 469: 106

Answer

$\frac{2x^2}{y}\sqrt {2xy}$

Work Step by Step

$\sqrt {\frac {24x^5}{3y}}$ $\sqrt {\frac {3*2*2^2*x^4*x}{3y}}$ $\sqrt {\frac {3*2*2^2*x^4*x}{3y}*\frac{3y}{3y}}$ $\sqrt {\frac {3^2*2*2^2*x^4*xy}{3^2y^2}}$ $6x^2/3y\sqrt {2xy}$ $\frac{2x^2}{y}\sqrt {2xy}$
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