Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 57

Answer

$\sqrt[6] 1372$

Work Step by Step

$\sqrt[3] 2\times\sqrt 7=2^{\frac{1}{3}}\times7^{\frac{1}{2}}=2^{\frac{2}{6}}\times7^{\frac{3}{6}}=(2^{2}\times7^{3})^{\frac{1}{6}}=(4\times343)^{\frac{1}{6}}=1372^{\frac{1}{6}}=\sqrt[6] 1372$
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