Answer
$3727 \frac{MeV}{c^2}$
Work Step by Step
Subtract the mass of 2 electrons from the mass of a helium atom:
$$(4.002603u) (\frac{931.5 MeV/c^2}{1u})-2(0.511 \frac{MeV}{c^2})$$
$$=3727 \frac{MeV}{c^2}$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 30 - Nuclear Physics and Radioactivity - Problems - Page 881: 5
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