Answer
2.224 MeV.
Work Step by Step
Deuterium has 1 proton and 1 neutron in the nucleus. Calculate the binding energy using the mass of ordinary hydrogen, and the mass of a neutron, which are found in Appendix B. The electron masses cancel.
$$E_{binding}=\left(m(^{1}_{1}H)+m(^{1}_{0}n)-m(^{2}_{1}H)\right)c^2$$
$$ =\left( (1.007825u)+(1.008665u)-(2.014102)\right)c^2\left( \frac{931.49MeV/c^2}{u}\right)$$
$$ =2.224MeV$$
