Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 30 - Nuclear Physics and Radioactivity - Problems - Page 881: 2

Answer

$1.9\times10^{-15}m$

Work Step by Step

The $\alpha$ particle is a helium nucleus. This has A = 4. Use equation 30–1. $$r=(1.2\times10^{-15}m)A^{1/3}=(1.2\times10^{-15}m)4^{1/3}=1.9 fm$$
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