Answer
7.699 MeV.
Work Step by Step
See Example 30-4.
$^{15}_{7}N$ has seven protons and eight neutrons. Calculate the binding energy using the masses of the components and the mass of the nucleus. See Appendix B.
$$E_{binding}=\left( 7m(^{1}_{1}H)+8m(^{1}_{0}n)-m(^{15}_{7}N)\right)c^2$$
$$ =\left( 7(1.007825u)+8(1.008665u)-(15.000109u)\right)c^2\left( \frac{931.49MeV/c^2}{u}\right)$$
$$ =115.49MeV$$
Binding energy per nucleon is 115.49MeV/15 nucleons = 7.699MeV/nucleon.
