Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 30 - Nuclear Physics and Radioactivity - Problems - Page 881: 22

Answer

$2.6\times10^{-12}m$

Work Step by Step

Find the wavelength from the energy difference between the states. $$\Delta E = hf=\frac{hc}{\lambda}$$ $$\lambda=\frac{hc}{\Delta E}$$ $$ =\frac{(6.63\times10^{-34}J \cdot s)(3.00 \times10^8 m/s)}{(0.48 MeV)(1.60\times10^{-13}J/MeV)}$$ $$=2.6\times10^{-12}m$$
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