Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 2 - Kinematics in One Dimension - Exercises and Problems: 33

Answer

(a) $x = 21~m$ (b) $v = 26~m/s$ (c) $a = 24~m/s^2$

Work Step by Step

(a) $x(t) = 2t^3+2t+1$ At t = 2 s: $x = (2)(2~s)^3+(2)(2~s)+1$ $x = 21~m$ (b) $v(t) = \frac{dx}{dt} = 6t^2+2$ At t = 2 s: $v = (6)(2~s)^2+2$ $v = 26~m/s$ (c) $a(t) = \frac{dv}{dt} = 12t$ At t = 2 s: $a = (12)(2~s)$ $a = 24~m/s^2$
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