## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

$v = 30 ~m/s$
The change in velocity will be equal to the area between the acceleration versus time graph and the x-axis. Therefore, $\Delta v = \frac{1}{2}(10~m/s^2)(6~s)$ $\Delta v = 30~m/s$ We can then find the velocity at t = 6 s; $v = v_0 + \Delta v$ $v = 0 + 30~m/s$ $v = 30 ~m/s$