## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

The watermelon and Superman will have covered the same distance when the watermelon passes Superman. Therefore; $d_{watermelon} = d_{super}$ $\frac{v+v_0}{2}~t = v_{super}~t$ $v = 2~v_{super}$ $v = (2)(35~m/s)$ $v = 70~m/s$ The watermelon is moving at a speed of 70 m/s when it passes Superman.