Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 2 - Kinematics in One Dimension - Exercises and Problems: 20

Answer

(a) The tower should be 78 meters high. (b) The impact velocity is 39 m/s

Work Step by Step

(a) We can find the vertical height $y$ that an object in freefall drops in 4.0 seconds. $y = \frac{1}{2}a_y~t^2$ $y = \frac{1}{2}(9.80~m/s^2)(4.0~s)^2$ $y = 78~m$ The tower should be 78 meters high. (b) We can find the impact velocity $v_y$. $v_y = v_{y0}+a_y~t$ $v_y = 0 + a_y~t$ $v_y = (9.80~m/s^2)(4.0~s)$ $v = 39~m/s$ The impact velocity is 39 m/s
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.