## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

$v = 16.0 ~m/s$
The change in velocity will be equal to the area between the acceleration versus time graph and the x-axis; $\Delta v = \frac{1}{2}(4.0~m/s^2)(4.0~s)$ $\Delta v = 8.0~m/s$ We can find the velocity at t = 4.0 s; $v = v_0 + \Delta v$ $v = 8.0~m/s + 8.0~m/s$ $v = 16.0 ~m/s$