## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson

# Chapter 2 - Kinematics in One Dimension - Exercises and Problems - Page 60: 23

#### Answer

The flea goes up to a height of 5.15 cm

#### Work Step by Step

We can find the velocity $v$ after the flea accelerates through the first 0.50 mm: $v^2= v_0^2+2ay = 0 + 2ay$ $v = \sqrt{2ay} = \sqrt{(2)(1000~m/s^2)(0.50\times 10^{-3}~m)}$ $v = 1.0~m/s$ We then find the distance the flea goes up after the initial period of acceleration; $y = \frac{0-v^2}{2a} = \frac{-(1.0~m/s)^2}{(2)(-9.80~m/s^2)}$ $y = 0.0510~m$ The total height is $0.0510$ m plus the initial 0.50 mm while the flea was accelerating upward. This makes the total height 0.0515 meters which is 5.15 cm.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.