Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 2 - Kinematics in One Dimension - Exercises and Problems - Page 60: 13


(a) $a = 2.68~m/s^2$ (b) $x = 134~m$ $x = 440~feet$

Work Step by Step

(a) We can convert the speed to units of m/s. So; $v = (60~mph)(\frac{1609~m}{1~mi})(\frac{1~h}{3600~s}) = 26.8~m/s$ $a = \frac{v-v_0}{t} = \frac{26.8~m/s-0}{10~s}$ $a = 2.68~m/s^2$ (b) $x = \frac{1}{2}at^2 = \frac{1}{2}(2.68~m/s^2)(10~s)^2$ $x = 134~m$ We can convert this distance to feet. Therefore; $x = (134~m)(\frac{3.28~feet}{1~m})$ $x = 440~feet$
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