Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems - Page 49: 43


44.1 m/s

Work Step by Step

$v^{2}=u^{2}+2ax$ $v=\sqrt (u^{2}+2ax)$ Let down be the positive direction When air resistance is absent, a=9.8 $m/s^{2}$ $v=\sqrt {((0)^{2}+2(9.8)(99.4))}$ $v\approx44.1\; m/s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.