Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems: 43


44.1 m/s

Work Step by Step

$v^{2}=u^{2}+2ax$ $v=\sqrt (u^{2}+2ax)$ Let down be the positive direction When air resistance is absent, a=9.8 $m/s^{2}$ $v=\sqrt {((0)^{2}+2(9.8)(99.4))}$ $v\approx44.1\; m/s$
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