Answer
44.1 m/s
Work Step by Step
$v^{2}=u^{2}+2ax$
$v=\sqrt (u^{2}+2ax)$
Let down be the positive direction
When air resistance is absent, a=9.8 $m/s^{2}$
$v=\sqrt {((0)^{2}+2(9.8)(99.4))}$
$v\approx44.1\; m/s$
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 2 - Kinematics in One Dimension - Problems - Page 49: 43
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