## Physics (10th Edition)

a) $1.6\; m/s^{2}$ b) $2.0\times 10^{1}\; m$
a) v = u+at $a = \frac{v-u}{t} = \frac{8.0-0}{5.0} = 1.6\; m/s^{2}$ b) $x = \frac{1}{2}(u+v)t = \frac{1}{2}(0+8.0)(5.0)=2.0\times 10^{1}\; m$