Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems - Page 49: 40


1.70 s

Work Step by Step

$x=vt-\frac{1}{2}at^{2}$ $(25.0+59.7)=(45.0)t-\frac{1}{2}(-5.70)t^{2}$ $84.7=45.0t+2.85t^{2}$ $2.85t^{2}+45.0t-84.7=0$ Using the quadratic formula: $t=\frac{-(45.0)±\sqrt ((45.0)^{2}-4(2.85)(-84.7)}{2(2.85)}$ $t\gt0$ hence $t=\frac{-(45.0)+\sqrt ((45.0)^{2}-4(2.85)(-84.7)}{2(2.85)}\approx 1.70s$
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