## Physics (10th Edition)

$x=vt-\frac{1}{2}at^{2}$ $(25.0+59.7)=(45.0)t-\frac{1}{2}(-5.70)t^{2}$ $84.7=45.0t+2.85t^{2}$ $2.85t^{2}+45.0t-84.7=0$ Using the quadratic formula: $t=\frac{-(45.0)±\sqrt ((45.0)^{2}-4(2.85)(-84.7)}{2(2.85)}$ $t\gt0$ hence $t=\frac{-(45.0)+\sqrt ((45.0)^{2}-4(2.85)(-84.7)}{2(2.85)}\approx 1.70s$