Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems - Page 49: 37


0.87 $m/s^{2}$

Work Step by Step

First car: $x=ut+\frac{1}{2}at^{2}$ $(2500)=(33)t+\frac{1}{2}(0)t^{2}$ $2500=33t$ $t=\frac{2500}{33}$ Second car: $x=ut+\frac{1}{2}at^{2}$ $(2500)=(0)(\frac{2500}{33})+\frac{1}{2}a(\frac{2500}{33})^{2}$ $a=2500\times2\times(\frac{33}{2500})^{2}\approx 0.87\; m/s^{2}$
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