Answer
0.87 $m/s^{2}$
Work Step by Step
First car:
$x=ut+\frac{1}{2}at^{2}$
$(2500)=(33)t+\frac{1}{2}(0)t^{2}$
$2500=33t$
$t=\frac{2500}{33}$
Second car:
$x=ut+\frac{1}{2}at^{2}$
$(2500)=(0)(\frac{2500}{33})+\frac{1}{2}a(\frac{2500}{33})^{2}$
$a=2500\times2\times(\frac{33}{2500})^{2}\approx 0.87\; m/s^{2}$
