## Physics (10th Edition)

0.87 $m/s^{2}$
First car: $x=ut+\frac{1}{2}at^{2}$ $(2500)=(33)t+\frac{1}{2}(0)t^{2}$ $2500=33t$ $t=\frac{2500}{33}$ Second car: $x=ut+\frac{1}{2}at^{2}$ $(2500)=(0)(\frac{2500}{33})+\frac{1}{2}a(\frac{2500}{33})^{2}$ $a=2500\times2\times(\frac{33}{2500})^{2}\approx 0.87\; m/s^{2}$