# Chapter 2 - Kinematics in One Dimension - Problems - Page 49: 27

a) 170 $cm/s^{2}$ b) 0.15 s

#### Work Step by Step

a) $v^{2} = u^{2} +2ax$ $a = \frac{v^{2} - u^{2}}{2x} = \frac{(26)^{2}-(0)^{2}}{2(2.0)} = 169 \approx 170 cm/s^{2}$ b) $x = \frac{1}{2}(u+v)t$ $t = \frac{2x}{u+v} = \frac{2(2.0)}{0+26} \approx 0.15 s$

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