Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems: 32

Answer

-22 $m/s^{2}$

Work Step by Step

We set up a system of linear equations: $x = ut + \frac{1}{2}at^{2} $ $0 = (5800)t + \frac{1}{2}(-15)t^{2}$ $t(5800-\frac{15}{2}t)=0$ $t=0, t=\frac{2320}{3}$ $0 = (8600)t + \frac{1}{2}(a)t^{2}$ $t(8600+\frac{1}{2}at)=0$ $t=0, t=\frac{-17200}{a}$ $\frac{2320}{3}=\frac{-17200}{a}$ $2320a=-51600$ $a\approx-22\; m/s^{2}$
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