Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems - Page 49: 29


Acceleration is $3.1\; m/s^{2}$ south

Work Step by Step

Let north be the positive direction. $v^{2}=u^{2}+2ax$ $a=\frac{v^{2}-u^{2}}{2x}=\frac{(6.1)^{2}-(69)^{2}}{2(750)}\approx-3.1\; m/s^{2}$
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