Physics (10th Edition)

Acceleration is $3.1\; m/s^{2}$ south
Let north be the positive direction. $v^{2}=u^{2}+2ax$ $a=\frac{v^{2}-u^{2}}{2x}=\frac{(6.1)^{2}-(69)^{2}}{2(750)}\approx-3.1\; m/s^{2}$