Answer
The work done on the object by the force is $~~100~J$
Work Step by Step
We can find the kinetic energy at the end of the 3.0 second interval:
$K_f = \frac{1}{2}mv^2$
$K_f = \frac{1}{2}(2.0~kg)(10~m/s)^2$
$K_f = 100~J$
Since the object was initially at rest, the initial kinetic energy is zero.
We can find the work done on the object by the force:
$W = K_f-K_i$
$W = 100~J-0$
$W = 100~J$
The work done on the object by the force is $~~100~J$.
