Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems - Page 174: 55a

Answer

In ten minutes, the work done by the force is $~~(1.83\times 10^5)~ft\cdot lb$

Work Step by Step

We can find the distance traveled in 10 minutes: $d = (6.0~mi/h)(\frac{1}{6}~h)(\frac{5280~ft}{1~mi}) = 5280~ft$ We can find the work done by the force in 10 minutes: $W = F~d~cos~\theta$ $W = (40~lb)~(5280~ft)~cos~30^{\circ}$ $W = (1.83\times 10^5)~ft\cdot lb$ In ten minutes, the work done by the force is $~~(1.83\times 10^5)~ft\cdot lb$.
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