Answer
The average power of the machine's force on the package is $~~8.4~W$
Work Step by Step
In part (a) we found that the work done on the package by the force is $~~101~J$
We can find the average power of the machine's force on the package:
$P = \frac{W}{t} = \frac{101~J}{12~s} = 8.4~W$
The average power of the machine's force on the package is $~~8.4~W$