Answer
The work done on the package by the force is $~~101~J$
Work Step by Step
We can find the work done in the $\hat{i}$-direction:
$W_i = F_i~(7.50~m-0.50~m)$
$W_i = (2.00~N)~(7.50~m-0.50~m)$
$W_i = 14.0~J$
We can find the work done in the $\hat{j}$-direction:
$W_j = F_j~(12.0~m-0.75~m)$
$W_j = (4.00~N)~(12.0~m-0.75~m)$
$W_j = 45.0~J$
We can find the work done in the $\hat{k}$-direction:
$W_k = F_k~(7.20~m-0.20~m)$
$W_k = (6.00~N)~(7.20~m-0.20~m)$
$W_k = 42.0~J$
We can find the work done on the package by the force:
$W = W_i+W_j+W_k$
$W = 14.0~J+45.0~J+42.0~J$
$W = 101~J$
The work done on the package by the force is $~~101~J$
