Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems - Page 174: 45

Answer

$4.9\times10^2 W$

Work Step by Step

By definition we know that $P=F.v$ $P=Fvcos\theta$ Put the values $P=122\times5cos37^{\circ}$ $P=487.17W$ $P=4.8717\times10^2W$ or after rounding, we get $P=4.9\times10^2W$
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