Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems - Page 174: 46

Answer

$2.7\times10^5 W$

Work Step by Step

Given that the speed of elevator is constant that's why there is no net force, hence tension in cable is equal to weight of the elevator. Mathematically: $T=mg$ Putting in the values $T=3\times10^3\times9.8=29400N$ Thus the work done by the tension in cable is $W=Td=29400\times210=6174000J=6.17\times10^6J$ By definition, the rate of doing work is called power so $P=\frac{W}{\Delta{t}}$ Enter the values $P=\frac{6.17\times10^6}{23}$ $P=2.7\times10^5W$
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