Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems - Page 174: 51a

Answer

The work done on the object by the force is $~~32.0~J$

Work Step by Step

We can find the work done in the x-direction: $W_x = F_x~(-5.00~m-3.00~m)$ $W_x = (3.00~N)~(-5.00~m-3.00~m)$ $W_x = -24.0~J$ We can find the work done in the y-direction: $W_y = F_y~[4.00~m-(-2.00~m)]$ $W_y = (7.00~N)~[4.00~m-(-2.00~m)]$ $W_y = 42.0~J$ We can find the work done in the z-direction: $W_z = F_z~(7.00~m-5.00~m)$ $W_z = (7.00~N)~(7.00~m-5.00~m)$ $W_z = 14.0~J$ We can find the work done on the object by the force: $W = W_x+W_y+W_z$ $W = -24.0~J+42.0~J+14.0~J$ $W = 32.0~J$ The work done on the object by the force is $~~32.0~J$
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