Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 24 - Electric Potential - Problems - Page 715: 83a

Answer

$V=7.19\times 10^{-10}V$

Work Step by Step

We know that $V=K\frac{q_1}{d_1}+K\frac{q_2}{d_2}$ We plugin the known values to obtain: $V=9\times 10^9\times \frac{-2\times 1.6\times 10^{-19}}{4}+9\times 10^9\times \frac{2\times 1.6\times 10^{-19}}{2}$ $V=7.19\times 10^{-10}V$
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