Answer
$V=3.6\times10^5V$
Work Step by Step
We know that
$V=K\frac{q}{r}$
We plug in the known values to obtain:
$V=9\times10^9\times\frac{4\times10^{-6}}{0.10}$
$V=360000V$
$V=3.6\times10^5V$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 24 - Electric Potential - Problems - Page 715: 73a
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