Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 24 - Electric Potential - Problems - Page 715: 70a

Answer

$U = (4.9\times 10^{-3}) J$

Work Step by Step

$U= \frac{1}{2}CV^{2}$ $U= \frac{1}{2} (200\times 10^{-12})(7.0 \times 10^{3})$ $U = (4.9\times 10^{-3}) J$
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