Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 24 - Electric Potential - Problems - Page 715: 78

Answer

0.957V

Work Step by Step

The total electric potential is given as: $V=K\frac{q_1}{R}+K\frac{q_2}{R}+K\frac{q_3}{R}$ We plug in the known values to obtain: $V=9\times 10^9\times \frac{4.52\times 10^{-12}}{8.50\times 10^{-2}}+9\times 10^9\times \frac{-2\times4.52\times 10^{-12}}{8.50\times 10^{-2}}+9\times 10^9\times \frac{3\times4.52\times 10^{-12}}{8.50\times 10^{-2}}$ Solving the equation, we find that: $V=0.957V$
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